Rael has 5-cent coins and 20-cent coins. The total value of all his coins is $34. He has 10 less 5-cent coins than 20-cent coins. How many coins does he have altogether?
|
5-cent |
20-cent |
Total |
Number |
1 u |
1 u + 10 |
2 u + 10 |
Value |
5 |
20 |
|
Total value |
5 u |
20 u + 200 |
25 u + 200 |
$1 = 100¢
$34 = 34 x 100 = 3400¢
Rael has 10 more 20-cent coins than 5-cent coins.
Number of 5-cent coins = 1 u
Number of 20-cent coins = 1 u + 10
Total value of 5-cent coins
= 5 x 1 u
= 5 u
Total value of 20-cent coins
= 20 x (1 u + 10)
= 20 u + 200
Total value of the coins
= 5 u + 20 u + 200
= 25 u + 200
25 u + 200 = 3400
25 u = 3400 - 200
25 u = 3200
1 u = 3200 ÷ 25 = 128
Total number of coins
= 1 u + (1 u + 10)
= 2 u + 10
= 2 x 128 + 10
= 256 + 10
= 266
Answer(s): 266