Cole has 5-cent coins and 10-cent coins. The total value of all his coins is $40. He has 13 less 5-cent coins than 10-cent coins. How many coins does he have altogether?
|
5-cent |
10-cent |
Total |
Number |
1 u |
1 u + 13 |
2 u + 13 |
Value |
5 |
10 |
|
Total value |
5 u |
10 u + 130 |
15 u + 130 |
$1 = 100¢
$40 = 40 x 100 = 4000¢
Cole has 13 more 10-cent coins than 5-cent coins.
Number of 5-cent coins = 1 u
Number of 10-cent coins = 1 u + 13
Total value of 5-cent coins
= 5 x 1 u
= 5 u
Total value of 10-cent coins
= 10 x (1 u + 13)
= 10 u + 130
Total value of the coins
= 5 u + 10 u + 130
= 15 u + 130
15 u + 130 = 4000
15 u = 4000 - 130
15 u = 3870
1 u = 3870 ÷ 15 = 258
Total number of coins
= 1 u + (1 u + 13)
= 2 u + 13
= 2 x 258 + 13
= 516 + 13
= 529
Answer(s): 529