Wesley has 5-cent coins and 10-cent coins. The total value of all his coins is $23. He has 17 less 5-cent coins than 10-cent coins. How many coins does he have altogether?
|
5-cent |
10-cent |
Total |
Number |
1 u |
1 u + 17 |
2 u + 17 |
Value |
5 |
10 |
|
Total value |
5 u |
10 u + 170 |
15 u + 170 |
$1 = 100¢
$23 = 23 x 100 = 2300¢
Wesley has 17 more 10-cent coins than 5-cent coins.
Number of 5-cent coins = 1 u
Number of 10-cent coins = 1 u + 17
Total value of 5-cent coins
= 5 x 1 u
= 5 u
Total value of 10-cent coins
= 10 x (1 u + 17)
= 10 u + 170
Total value of the coins
= 5 u + 10 u + 170
= 15 u + 170
15 u + 170 = 2300
15 u = 2300 - 170
15 u = 2130
1 u = 2130 ÷ 15 = 142
Total number of coins
= 1 u + (1 u + 17)
= 2 u + 17
= 2 x 142 + 17
= 284 + 17
= 301
Answer(s): 301