Rael has 10-cent coins and 50-cent coins. The total value of all his coins is $32. He has 4 less 10-cent coins than 50-cent coins. How many coins does he have altogether?
|
10-cent |
50-cent |
Total |
Number |
1 u |
1 u + 4 |
2 u + 4 |
Value |
10 |
50 |
|
Total value |
10 u |
50 u + 200 |
60 u + 200 |
$1 = 100¢
$32 = 32 x 100 = 3200¢
Rael has 4 more 50-cent coins than 10-cent coins.
Number of 10-cent coins = 1 u
Number of 50-cent coins = 1 u + 4
Total value of 10-cent coins
= 10 x 1 u
= 10 u
Total value of 50-cent coins
= 50 x (1 u + 4)
= 50 u + 200
Total value of the coins
= 10 u + 50 u + 200
= 60 u + 200
60 u + 200 = 3200
60 u = 3200 - 200
60 u = 3000
1 u = 3000 ÷ 60 = 50
Total number of coins
= 1 u + (1 u + 4)
= 2 u + 4
= 2 x 50 + 4
= 100 + 4
= 104
Answer(s): 104