Liam has 5-cent coins and 10-cent coins. The total value of all his coins is $18. He has 6 less 5-cent coins than 10-cent coins. How many coins does he have altogether?
|
5-cent |
10-cent |
Total |
Number |
1 u |
1 u + 6 |
2 u + 6 |
Value |
5 |
10 |
|
Total value |
5 u |
10 u + 60 |
15 u + 60 |
$1 = 100¢
$18 = 18 x 100 = 1800¢
Liam has 6 more 10-cent coins than 5-cent coins.
Number of 5-cent coins = 1 u
Number of 10-cent coins = 1 u + 6
Total value of 5-cent coins
= 5 x 1 u
= 5 u
Total value of 10-cent coins
= 10 x (1 u + 6)
= 10 u + 60
Total value of the coins
= 5 u + 10 u + 60
= 15 u + 60
15 u + 60 = 1800
15 u = 1800 - 60
15 u = 1740
1 u = 1740 ÷ 15 = 116
Total number of coins
= 1 u + (1 u + 6)
= 2 u + 6
= 2 x 116 + 6
= 232 + 6
= 238
Answer(s): 238