Howard has 10-cent coins and 20-cent coins. The total value of all his coins is $25. He has 2 less 10-cent coins than 20-cent coins. How many coins does he have altogether?
|
10-cent |
20-cent |
Total |
Number |
1 u |
1 u + 2 |
2 u + 2 |
Value |
10 |
20 |
|
Total value |
10 u |
20 u + 40 |
30 u + 40 |
$1 = 100¢
$25 = 25 x 100 = 2500¢
Howard has 2 more 20-cent coins than 10-cent coins.
Number of 10-cent coins = 1 u
Number of 20-cent coins = 1 u + 2
Total value of 10-cent coins
= 10 x 1 u
= 10 u
Total value of 20-cent coins
= 20 x (1 u + 2)
= 20 u + 40
Total value of the coins
= 10 u + 20 u + 40
= 30 u + 40
30 u + 40 = 2500
30 u = 2500 - 40
30 u = 2460
1 u = 2460 ÷ 30 = 82
Total number of coins
= 1 u + (1 u + 2)
= 2 u + 2
= 2 x 82 + 2
= 164 + 2
= 166
Answer(s): 166