Justin has 5-cent coins and 20-cent coins. The total value of all his coins is $36. He has 15 less 5-cent coins than 20-cent coins. How many coins does he have altogether?
|
5-cent |
20-cent |
Total |
Number |
1 u |
1 u + 15 |
2 u + 15 |
Value |
5 |
20 |
|
Total value |
5 u |
20 u + 300 |
25 u + 300 |
$1 = 100¢
$36 = 36 x 100 = 3600¢
Justin has 15 more 20-cent coins than 5-cent coins.
Number of 5-cent coins = 1 u
Number of 20-cent coins = 1 u + 15
Total value of 5-cent coins
= 5 x 1 u
= 5 u
Total value of 20-cent coins
= 20 x (1 u + 15)
= 20 u + 300
Total value of the coins
= 5 u + 20 u + 300
= 25 u + 300
25 u + 300 = 3600
25 u = 3600 - 300
25 u = 3300
1 u = 3300 ÷ 25 = 132
Total number of coins
= 1 u + (1 u + 15)
= 2 u + 15
= 2 x 132 + 15
= 264 + 15
= 279
Answer(s): 279