Nick has 20-cent coins and 50-cent coins. The total value of all his coins is $14. He has 14 less 20-cent coins than 50-cent coins. How many coins does he have altogether?
|
20-cent |
50-cent |
Total |
Number |
1 u |
1 u + 14 |
2 u + 14 |
Value |
20 |
50 |
|
Total value |
20 u |
50 u + 700 |
70 u + 700 |
$1 = 100¢
$14 = 14 x 100 = 1400¢
Nick has 14 more 50-cent coins than 20-cent coins.
Number of 20-cent coins = 1 u
Number of 50-cent coins = 1 u + 14
Total value of 20-cent coins
= 20 x 1 u
= 20 u
Total value of 50-cent coins
= 50 x (1 u + 14)
= 50 u + 700
Total value of the coins
= 20 u + 50 u + 700
= 70 u + 700
70 u + 700 = 1400
70 u = 1400 - 700
70 u = 700
1 u = 700 ÷ 70 = 10
Total number of coins
= 1 u + (1 u + 14)
= 2 u + 14
= 2 x 10 + 14
= 20 + 14
= 34
Answer(s): 34