Ahmad has 10-cent coins and 50-cent coins. The total value of all his coins is $23. He has 16 less 10-cent coins than 50-cent coins. How many coins does he have altogether?
|
10-cent |
50-cent |
Total |
Number |
1 u |
1 u + 16 |
2 u + 16 |
Value |
10 |
50 |
|
Total value |
10 u |
50 u + 800 |
60 u + 800 |
$1 = 100¢
$23 = 23 x 100 = 2300¢
Ahmad has 16 more 50-cent coins than 10-cent coins.
Number of 10-cent coins = 1 u
Number of 50-cent coins = 1 u + 16
Total value of 10-cent coins
= 10 x 1 u
= 10 u
Total value of 50-cent coins
= 50 x (1 u + 16)
= 50 u + 800
Total value of the coins
= 10 u + 50 u + 800
= 60 u + 800
60 u + 800 = 2300
60 u = 2300 - 800
60 u = 1500
1 u = 1500 ÷ 60 = 25
Total number of coins
= 1 u + (1 u + 16)
= 2 u + 16
= 2 x 25 + 16
= 50 + 16
= 66
Answer(s): 66