Howard has 5-cent coins and 50-cent coins. The total value of all his coins is $36. He has 17 less 5-cent coins than 50-cent coins. How many coins does he have altogether?
|
5-cent |
50-cent |
Total |
Number |
1 u |
1 u + 17 |
2 u + 17 |
Value |
5 |
50 |
|
Total value |
5 u |
50 u + 850 |
55 u + 850 |
$1 = 100¢
$36 = 36 x 100 = 3600¢
Howard has 17 more 50-cent coins than 5-cent coins.
Number of 5-cent coins = 1 u
Number of 50-cent coins = 1 u + 17
Total value of 5-cent coins
= 5 x 1 u
= 5 u
Total value of 50-cent coins
= 50 x (1 u + 17)
= 50 u + 850
Total value of the coins
= 5 u + 50 u + 850
= 55 u + 850
55 u + 850 = 3600
55 u = 3600 - 850
55 u = 2750
1 u = 2750 ÷ 55 = 50
Total number of coins
= 1 u + (1 u + 17)
= 2 u + 17
= 2 x 50 + 17
= 100 + 17
= 117
Answer(s): 117