Bobby has 10-cent coins and 50-cent coins. The total value of all his coins is $31. He has 8 less 10-cent coins than 50-cent coins. How many coins does he have altogether?
|
10-cent |
50-cent |
Total |
Number |
1 u |
1 u + 8 |
2 u + 8 |
Value |
10 |
50 |
|
Total value |
10 u |
50 u + 400 |
60 u + 400 |
$1 = 100¢
$31 = 31 x 100 = 3100¢
Bobby has 8 more 50-cent coins than 10-cent coins.
Number of 10-cent coins = 1 u
Number of 50-cent coins = 1 u + 8
Total value of 10-cent coins
= 10 x 1 u
= 10 u
Total value of 50-cent coins
= 50 x (1 u + 8)
= 50 u + 400
Total value of the coins
= 10 u + 50 u + 400
= 60 u + 400
60 u + 400 = 3100
60 u = 3100 - 400
60 u = 2700
1 u = 2700 ÷ 60 = 45
Total number of coins
= 1 u + (1 u + 8)
= 2 u + 8
= 2 x 45 + 8
= 90 + 8
= 98
Answer(s): 98