Fred has 10-cent coins and 50-cent coins. The total value of all his coins is $37. He has 14 less 10-cent coins than 50-cent coins. How many coins does he have altogether?
| |
10-cent |
50-cent |
Total |
| Number |
1 u |
1 u + 14 |
2 u + 14 |
| Value |
10 |
50 |
|
| Total value |
10 u |
50 u + 700 |
60 u + 700 |
$1 = 100¢
$37 = 37 x 100 = 3700¢
Fred has 14 more 50-cent coins than 10-cent coins.
Number of 10-cent coins = 1 u
Number of 50-cent coins = 1 u + 14
Total value of 10-cent coins
= 10 x 1 u
= 10 u
Total value of 50-cent coins
= 50 x (1 u + 14)
= 50 u + 700
Total value of the coins
= 10 u + 50 u + 700
= 60 u + 700
60 u + 700 = 3700
60 u = 3700 - 700
60 u = 3000
1 u = 3000 ÷ 60 = 50
Total number of coins
= 1 u + (1 u + 14)
= 2 u + 14
= 2 x 50 + 14
= 100 + 14
= 114
Answer(s): 114
