Perry has 10-cent coins and 20-cent coins. The total value of all his coins is $10. He has 14 less 10-cent coins than 20-cent coins. How many coins does he have altogether?
|
10-cent |
20-cent |
Total |
Number |
1 u |
1 u + 14 |
2 u + 14 |
Value |
10 |
20 |
|
Total value |
10 u |
20 u + 280 |
30 u + 280 |
$1 = 100¢
$10 = 10 x 100 = 1000¢
Perry has 14 more 20-cent coins than 10-cent coins.
Number of 10-cent coins = 1 u
Number of 20-cent coins = 1 u + 14
Total value of 10-cent coins
= 10 x 1 u
= 10 u
Total value of 20-cent coins
= 20 x (1 u + 14)
= 20 u + 280
Total value of the coins
= 10 u + 20 u + 280
= 30 u + 280
30 u + 280 = 1000
30 u = 1000 - 280
30 u = 720
1 u = 720 ÷ 30 = 24
Total number of coins
= 1 u + (1 u + 14)
= 2 u + 14
= 2 x 24 + 14
= 48 + 14
= 62
Answer(s): 62