Xylia gave 3 coins to every girl and 8 coins to every boy in her class. There were 2 more girls than boys in the class. She gave away a total of 61 coins.
- How many children were there in the class?
- How many less coins were given to the girls than the boys?
(a)
There were more girls than boys in class.
If we remove the 2 extra girls, the number of girls and boys will be the same.
Xylia would give away less coins.
Number of less coins that Xylia needed to give away if there was 2 less girls
= 2 x 3
= 6
Number of coins she would need if there was 2 less girls
= 61 - 6
= 55
Number of coins to give for every 1 girl and 1 boy
= 3 + 8
= 11
Number of sets of 1 girl and 1 boy
= 55 ÷ 11
= 5
Number of boys = 5
Number of girls
= 5 + 2
= 7
Number of children
= 5 + 7
= 12
(b)
Number of coins given to the girls
= 7 x 3
= 21
Number of coins given to the boys
= 5 x 8
= 40
Number of less coins given to the girls than the boys
= 40 - 21
= 19
Answer(s): (a) 12; (b) 19
