At first, Pierre had 104 more gold beads than silver beads in a box. Each day, he took out 10 gold beads and 2 silver beads from the box. After some time, he only had 24 silver beads left in the box.
- How many beads did Pierre take out from the box altogether?
- How many silver beads did Pierre have at first?
| |
Gold beads |
Silver beads |
Comparing gold beads
and silver beads at first |
104 more |
|
| Before |
10 u |
2 u + 24 |
| Change |
- 10 u |
- 2 u |
| After |
0 |
24 |
(a)
If another 104 silver beads are added into the box at first, the number of gold and silver beads will be the same.
10 u = 2 u + 24 + 104
10 u - 2 u = 24 + 104
8 u = 128
1 u = 128 ÷ 8 = 16
Number of beads that Pierre took out
= 10 u + 2 u
= 12 u
= 12 x 16
= 192
(b)
Number of beads that Pierre had at first
= 192 + 24
= 216
Answer(s): (a) 192; (b) 216
