Elyse had some $1-notes and some $5-notes.
711 of the notes were $1-notes and the rest were $5-notes. After Elyse had spent $1360 worth of $5-notes and
47 of $1-notes, she had
37 of the notes left. Find the number of $5-notes Elyse had left.
| |
$1-notes |
$5-notes |
Total |
Comparing $1-notes
and $5-notes
at first |
7x7 =
49 u |
4x7 =
28 u |
11x7 =
77 u |
| Before |
7x7 =
49 u |
|
7x11 =
77 u |
| Change |
- 4x7 =
- 28 u |
- 272 |
- 4x11 =
- 44 u |
| After |
3x7=
21 u |
28 u - 272 |
3x11 =
33 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 11 and 7 is 77.
The number of $1-notes is repeated.
Number of $5-notes
= 1360 ÷ 5
= 272
Total number of notes spent = 28 u + 272
28 u + 272 = 44 u
44 u - 28 u = 272
16 u = 272
1 u = 272 ÷ 16 = 17
Number of $5-notes that Elyse had left
= 28 u - 272
= 28 x 17 - 272
= 204
Answer(s): 204
