Linda had some $50-notes and some $1-notes.
35 of the notes were $50-notes and the rest were $1-notes. After Linda had spent $152 worth of $1-notes and
13 of $50-notes, she had
47 of the notes left. Find the number of $1-notes Linda had left.
| |
$50-notes |
$1-notes |
Total |
Comparing $50-notes
and $1-notes
at first |
3x7 =
21 u |
2x7 =
14 u |
5x7 =
35 u |
| Before |
3x7 =
21 u |
|
7x5 =
35 u |
| Change |
- 1x7 =
- 7 u |
- 152 |
- 3x5 =
- 15 u |
| After |
2x7=
14 u |
14 u - 152 |
4x5 =
20 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 5 and 7 is 35.
The number of $50-notes is repeated.
Number of $1-notes
= 152 ÷ 1
= 152
Total number of notes spent = 7 u + 152
7 u + 152 = 15 u
15 u - 7 u = 152
8 u = 152
1 u = 152 ÷ 8 = 19
Number of $1-notes that Linda had left
= 14 u - 152
= 14 x 19 - 152
= 114
Answer(s): 114
