Hazel had some $10-notes and some $5-notes.
58 of the-notes were $10-notes and the rest were $5-notes. After Hazel had spent $2860 worth of $5-notes and
25 of $10-notes, she had
15 of the notes left. Find the number of $10-notes Hazel had left.
| |
$10-notes |
$5-notes |
Total |
Comparing $10-notes
and $5-notes
at first |
5x5 =
25 u |
3x5 =
15 u |
8x5 =
40 u |
| Before |
5x5 =
25 u |
|
5x8 =
40 u |
| Change |
- 2x5 =
- 10 u |
- 572 |
- 4x8 =
- 32 u |
| After |
3x5=
15 u |
15 u - 572 |
1x8 =
8 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 8 and 5 is 40.
The number of $10-notes is repeated.
Number of $5-notes
= 2860 ÷ 5
= 572
Total number of notes spent = 10 u + 572
10 u + 572 = 32 u
32 u - 10 u = 572
22 u = 572
1 u = 572 ÷ 22 = 26
Number of $10-notes that Hazel had left
= 15 u
= 15 x 26
= 390
Answer(s): 390
