Gillian had some $1-notes and some $2-notes.
35 of the-notes were $1-notes and the rest were $2-notes. After Gillian had spent $192 worth of $2-notes and
23 of $1-notes, she had
511 of the notes left. Find the number of $1-notes Gillian had left.
| |
$1-notes |
$2-notes |
Total |
Comparing $1-notes
and $2-notes
at first |
3x11 =
33 u |
2x11 =
22 u |
5x11 =
55 u |
| Before |
3x11 =
33 u |
|
11x5 =
55 u |
| Change |
- 2x11 =
- 22 u |
- 96 |
- 6x5 =
- 30 u |
| After |
1x11=
11 u |
22 u - 96 |
5x5 =
25 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 5 and 11 is 55.
The number of $1-notes is repeated.
Number of $2-notes
= 192 ÷ 2
= 96
Total number of notes spent = 22 u + 96
22 u + 96 = 30 u
30 u - 22 u = 96
8 u = 96
1 u = 96 ÷ 8 = 12
Number of $1-notes that Gillian had left
= 11 u
= 11 x 12
= 132
Answer(s): 132
