Esther had some $5-notes and some $1-notes.
611 of the-notes were $5-notes and the rest were $1-notes. After Esther had spent $532 worth of $1-notes and
56 of $5-notes, she had
15 of the notes left. Find the number of $5-notes Esther had left.
| |
$5-notes |
$1-notes |
Total |
Comparing $5-notes
and $1-notes
at first |
6x5 =
30 u |
5x5 =
25 u |
11x5 =
55 u |
| Before |
6x5 =
30 u |
|
5x11 =
55 u |
| Change |
- 5x5 =
- 25 u |
- 532 |
- 4x11 =
- 44 u |
| After |
1x5=
5 u |
25 u - 532 |
1x11 =
11 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 11 and 5 is 55.
The number of $5-notes is repeated.
Number of $1-notes
= 532 ÷ 1
= 532
Total number of notes spent = 25 u + 532
25 u + 532 = 44 u
44 u - 25 u = 532
19 u = 532
1 u = 532 ÷ 19 = 28
Number of $5-notes that Esther had left
= 5 u
= 5 x 28
= 140
Answer(s): 140
