Kylie had some $50-notes and some $10-notes.
211 of the-notes were $50-notes and the rest were $10-notes. After Kylie had spent $4250 worth of $10-notes and
12 of $50-notes, she had
35 of the notes left. Find the number of $50-notes Kylie had left.
| |
$50-notes |
$10-notes |
Total |
Comparing $50-notes
and $10-notes
at first |
2x5 =
10 u |
9x5 =
45 u |
11x5 =
55 u |
| Before |
2x5 =
10 u |
|
5x11 =
55 u |
| Change |
- 1x5 =
- 5 u |
- 425 |
- 2x11 =
- 22 u |
| After |
1x5=
5 u |
45 u - 425 |
3x11 =
33 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 11 and 5 is 55.
The number of $50-notes is repeated.
Number of $10-notes
= 4250 ÷ 10
= 425
Total number of notes spent = 5 u + 425
5 u + 425 = 22 u
22 u - 5 u = 425
17 u = 425
1 u = 425 ÷ 17 = 25
Number of $50-notes that Kylie had left
= 5 u
= 5 x 25
= 125
Answer(s): 125
