Xylia had some $50-notes and some $2-notes.
611 of the-notes were $50-notes and the rest were $2-notes. After Xylia had spent $612 worth of $2-notes and
16 of $50-notes, she had
35 of the notes left. Find the number of $50-notes Xylia had left.
| |
$50-notes |
$2-notes |
Total |
Comparing $50-notes
and $2-notes
at first |
6x5 =
30 u |
5x5 =
25 u |
11x5 =
55 u |
| Before |
6x5 =
30 u |
|
5x11 =
55 u |
| Change |
- 1x5 =
- 5 u |
- 306 |
- 2x11 =
- 22 u |
| After |
5x5=
25 u |
25 u - 306 |
3x11 =
33 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 11 and 5 is 55.
The number of $50-notes is repeated.
Number of $2-notes
= 612 ÷ 2
= 306
Total number of notes spent = 5 u + 306
5 u + 306 = 22 u
22 u - 5 u = 306
17 u = 306
1 u = 306 ÷ 17 = 18
Number of $50-notes that Xylia had left
= 25 u
= 25 x 18
= 450
Answer(s): 450
