Kimberly had some $50-notes and some $10-notes.
512 of the notes were $50-notes and the rest were $10-notes. After Kimberly had spent $1710 worth of $10-notes and
35 of $50-notes, she had
38 of the notes left. Find the number of $10-notes Kimberly had left.
| |
$50-notes |
$10-notes |
Total |
Comparing $50-notes
and $10-notes
at first |
5x2 =
10 u |
7x2 =
14 u |
12x2 =
24 u |
| Before |
5x2 =
10 u |
|
8x3 =
24 u |
| Change |
- 3x2 =
- 6 u |
- 171 |
- 5x3 =
- 15 u |
| After |
2x2=
4 u |
14 u - 171 |
3x3 =
9 u |
The total number of notes at first is the repeated. Make the total number of notes the same. LCM of 12 and 8 is 24.
The number of $50-notes is repeated.
Number of $10-notes
= 1710 ÷ 10
= 171
Total number of notes spent = 6 u + 171
6 u + 171 = 15 u
15 u - 6 u = 171
9 u = 171
1 u = 171 ÷ 9 = 19
Number of $10-notes that Kimberly had left
= 14 u - 171
= 14 x 19 - 171
= 95
Answer(s): 95
