Raeann, Tiffany and Xylia bought a gift for their niece. They shared the cost equally between them. Raeann used
49 of her savings, Tiffany used
27 of her savings and Xylia used
57 of her savings. Raeann and Xylia had $198 left. How much did each girl pay for the gift?
The amount spent by each girl is the same. Make the numerators the same.
LCM of 4, 2 and 5 = 20
4x59x5 of Raeann's savings =
2x107x10 of Tiffany's savings =
5x47x4 of Xylia savings
2045 of Raeann's savings =
2070 of Tiffany's savings =
2028 of Xylia's savings
|
Raeann |
Tiffany |
Xylia |
Before |
45 u |
70 u |
28 u |
Change |
- 20 u |
- 20 u |
- 20 u |
After |
25 u |
50 u |
8 u |
Savings that Raeann had left
= 45 u - 20 u
= 25 u
Savings that Xylia had left
= 28 u - 20 u
= 8 u
Total savings that Raeann and Xylia had left
= 25 u + 8 u
= 33 u
33 u = 198
1 u = 198 ÷ 33 = 6
Amount that each girl paid
= 20 u
= 20 x 6
= $120
Answer(s): $120