Ethan, Dylan and Charlie collected coins in the ratio of 8 : 7 : 4. After Charlie gave
45 to Ethan and Dylan, Charlie had 166 less coins than Ethan. The number of coins that Dylan had increased by 30%. How many coins did Ethan and Charlie have in the end?
| |
Ethan |
Dylan |
Charlie |
| Before |
8 u |
7 u |
4 u |
| Change |
+ 1.1 u |
+ 2.1 u |
- 3.2 u |
| After |
9.1 u |
9.1 u |
0.8 u |
Number of coins that Charlie gave to Ethan and Dylan
=
45 x 4 u
= 3.2 u
Number of coins that Dylan received from Charlie
=
30100 x 7 u
= 2.1 u
Number of coins that Ethan received from Charlie
= 3.2 u - 2.1 u
= 1.1 u
Number of less coins that Charlie had less than Ethan
= 9.1 u - 0.8 u
= 8.3 u
8.3 u = 166
1 u = 166 ÷ 8.3 = 20
Number of coins that Ethan and Charlie had
= 9.1 u + 0.8 u
= 9.9 u
= 9.9 x 20
= 198
Answer(s): 198
