Owen, Simon and Chan collected coins in the ratio of 12 : 8 : 7. After Chan gave
45 to Owen and Simon, Chan had 300 less coins than Owen. The number of coins that Simon had increased by 15%. How many coins did Owen and Chan have in the end?
| |
Owen |
Simon |
Chan |
| Before |
12 u |
8 u |
7 u |
| Change |
+ 4.4 u |
+ 1.2 u |
- 5.6 u |
| After |
16.4 u |
9.2 u |
1.4 u |
Number of coins that Chan gave to Owen and Simon
=
45 x 7 u
= 5.6 u
Number of coins that Simon received from Chan
=
15100 x 8 u
= 1.2 u
Number of coins that Owen received from Chan
= 5.6 u - 1.2 u
= 4.4 u
Number of less coins that Chan had less than Owen
= 16.4 u - 1.4 u
= 15 u
15 u = 300
1 u = 300 ÷ 15 = 20
Number of coins that Owen and Chan had
= 16.4 u + 1.4 u
= 17.8 u
= 17.8 x 20
= 356
Answer(s): 356
