Reggie, Justin and Clifford collected coins in the ratio of 11 : 8 : 10. After Clifford gave ³₁₀ to Reggie and Justin, Clifford had 108 less coins than Reggie. The number of coins that Justin had increased by 20%. How many coins did Reggie and Clifford have in the end?

	Reggie	Justin	Clifford
Before	11 u	8 u	10 u
Change	+ 1.4 u	+ 1.6 u	- 3 u
After	12.4 u	9.6 u	7 u

Number of coins that Clifford gave to Reggie and Justin
= ³₁₀ x 10 u
= 3 u

Number of coins that Justin received from Clifford
= ²⁰₁₀₀ x 8 u
= 1.6 u

Number of coins that Reggie received from Clifford
= 3 u - 1.6 u
= 1.4 u

Number of less coins that Clifford had less than Reggie
= 12.4 u - 7 u 
= 5.4 u

5.4 u = 108

1 u = 108 ÷ 5.4 = 20

Number of coins that Reggie and Clifford had
= 12.4 u + 7 u
= 19.4 u
= 19.4 x 20
= 388

Answer(s): 388