Cole, Simon and Colin collected coins in the ratio of 7 : 6 : 9. After Colin gave
710 to Cole and Simon, Colin had 210 less coins than Cole. The number of coins that Simon had increased by 60%. How many coins did Cole and Colin have in the end?
| |
Cole |
Simon |
Colin |
| Before |
7 u |
6 u |
9 u |
| Change |
+ 2.7 u |
+ 3.6 u |
- 6.3 u |
| After |
9.7 u |
9.6 u |
2.7 u |
Number of coins that Colin gave to Cole and Simon
=
710 x 9 u
= 6.3 u
Number of coins that Simon received from Colin
=
60100 x 6 u
= 3.6 u
Number of coins that Cole received from Colin
= 6.3 u - 3.6 u
= 2.7 u
Number of less coins that Colin had less than Cole
= 9.7 u - 2.7 u
= 7 u
7 u = 210
1 u = 210 ÷ 7 = 30
Number of coins that Cole and Colin had
= 9.7 u + 2.7 u
= 12.4 u
= 12.4 x 30
= 372
Answer(s): 372
