Bryan, Eric and Colin collected coins in the ratio of 9 : 7 : 8. After Colin gave
710 to Bryan and Eric, Colin had 94 less coins than Bryan. The number of coins that Eric had increased by 40%. How many coins did Bryan and Colin have in the end?
| |
Bryan |
Eric |
Colin |
| Before |
9 u |
7 u |
8 u |
| Change |
+ 2.8 u |
+ 2.8 u |
- 5.6 u |
| After |
11.8 u |
9.8 u |
2.4 u |
Number of coins that Colin gave to Bryan and Eric
=
710 x 8 u
= 5.6 u
Number of coins that Eric received from Colin
=
40100 x 7 u
= 2.8 u
Number of coins that Bryan received from Colin
= 5.6 u - 2.8 u
= 2.8 u
Number of less coins that Colin had less than Bryan
= 11.8 u - 2.4 u
= 9.4 u
9.4 u = 94
1 u = 94 ÷ 9.4 = 10
Number of coins that Bryan and Colin had
= 11.8 u + 2.4 u
= 14.2 u
= 14.2 x 10
= 142
Answer(s): 142
