Ian, Riordan and Charles collected coins in the ratio of 9 : 4 : 10. After Charles gave
34 to Ian and Riordan, Charles had 340 less coins than Ian. The number of coins that Riordan had increased by 180%. How many coins did Ian and Charles have in the end?
| |
Ian |
Riordan |
Charles |
| Before |
9 u |
4 u |
10 u |
| Change |
+ 0.3 u |
+ 7.2 u |
- 7.5 u |
| After |
9.3 u |
11.2 u |
2.5 u |
Number of coins that Charles gave to Ian and Riordan
=
34 x 10 u
= 7.5 u
Number of coins that Riordan received from Charles
=
180100 x 4 u
= 7.2 u
Number of coins that Ian received from Charles
= 7.5 u - 7.2 u
= 0.3 u
Number of less coins that Charles had less than Ian
= 9.3 u - 2.5 u
= 6.8 u
6.8 u = 340
1 u = 340 ÷ 6.8 = 50
Number of coins that Ian and Charles had
= 9.3 u + 2.5 u
= 11.8 u
= 11.8 x 50
= 590
Answer(s): 590
