Bobby, Flynn and Charlie collected coins in the ratio of 9 : 7 : 10. After Charlie gave
710 to Bobby and Flynn, Charlie had 176 less coins than Bobby. The number of coins that Flynn had increased by 60%. How many coins did Bobby and Charlie have in the end?
|
Bobby |
Flynn |
Charlie |
Before |
9 u |
7 u |
10 u |
Change |
+ 2.8 u |
+ 4.2 u |
- 7 u |
After |
11.8 u |
11.2 u |
3 u |
Number of coins that Charlie gave to Bobby and Flynn
=
710 x 10 u
= 7 u
Number of coins that Flynn received from Charlie
=
60100 x 7 u
= 4.2 u
Number of coins that Bobby received from Charlie
= 7 u - 4.2 u
= 2.8 u
Number of less coins that Charlie had less than Bobby
= 11.8 u - 3 u
= 8.8 u
8.8 u = 176
1 u = 176 ÷ 8.8 = 20
Number of coins that Bobby and Charlie had
= 11.8 u + 3 u
= 14.8 u
= 14.8 x 20
= 296
Answer(s): 296