Paul, Riordan and Chen collected stamps in the ratio of 10 : 9 : 9. After Chen gave
710 to Paul and Riordan, Chen had 354 less stamps than Paul. The number of stamps that Riordan had increased by 20%. How many stamps did Paul and Chen have in the end?
| |
Paul |
Riordan |
Chen |
| Before |
10 u |
9 u |
9 u |
| Change |
+ 4.5 u |
+ 1.8 u |
- 6.3 u |
| After |
14.5 u |
10.8 u |
2.7 u |
Number of stamps that Chen gave to Paul and Riordan
=
710 x 9 u
= 6.3 u
Number of stamps that Riordan received from Chen
=
20100 x 9 u
= 1.8 u
Number of stamps that Paul received from Chen
= 6.3 u - 1.8 u
= 4.5 u
Number of less stamps that Chen had less than Paul
= 14.5 u - 2.7 u
= 11.8 u
11.8 u = 354
1 u = 354 ÷ 11.8 = 30
Number of stamps that Paul and Chen had
= 14.5 u + 2.7 u
= 17.2 u
= 17.2 x 30
= 516
Answer(s): 516
