Albert, Paul and Cole collected coins in the ratio of 9 : 4 : 5. After Cole gave
35 to Albert and Paul, Cole had 164 less coins than Albert. The number of coins that Paul had increased by 45%. How many coins did Albert and Cole have in the end?
| |
Albert |
Paul |
Cole |
| Before |
9 u |
4 u |
5 u |
| Change |
+ 1.2 u |
+ 1.8 u |
- 3 u |
| After |
10.2 u |
5.8 u |
2 u |
Number of coins that Cole gave to Albert and Paul
=
35 x 5 u
= 3 u
Number of coins that Paul received from Cole
=
45100 x 4 u
= 1.8 u
Number of coins that Albert received from Cole
= 3 u - 1.8 u
= 1.2 u
Number of less coins that Cole had less than Albert
= 10.2 u - 2 u
= 8.2 u
8.2 u = 164
1 u = 164 ÷ 8.2 = 20
Number of coins that Albert and Cole had
= 10.2 u + 2 u
= 12.2 u
= 12.2 x 20
= 244
Answer(s): 244
