Fabian, Asher and Chan collected coins in the ratio of 10 : 9 : 6. After Chan gave
45 to Fabian and Asher, Chan had 200 less coins than Fabian. The number of coins that Asher had increased by 40%. How many coins did Fabian and Chan have in the end?
| |
Fabian |
Asher |
Chan |
| Before |
10 u |
9 u |
6 u |
| Change |
+ 1.2 u |
+ 3.6 u |
- 4.8 u |
| After |
11.2 u |
12.6 u |
1.2 u |
Number of coins that Chan gave to Fabian and Asher
=
45 x 6 u
= 4.8 u
Number of coins that Asher received from Chan
=
40100 x 9 u
= 3.6 u
Number of coins that Fabian received from Chan
= 4.8 u - 3.6 u
= 1.2 u
Number of less coins that Chan had less than Fabian
= 11.2 u - 1.2 u
= 10 u
10 u = 200
1 u = 200 ÷ 10 = 20
Number of coins that Fabian and Chan had
= 11.2 u + 1.2 u
= 12.4 u
= 12.4 x 20
= 248
Answer(s): 248
