Brandon, Simon and Clark collected coins in the ratio of 8 : 5 : 8. After Clark gave
45 to Brandon and Simon, Clark had 440 less coins than Brandon. The number of coins that Simon had increased by 80%. How many coins did Brandon and Clark have in the end?
| |
Brandon |
Simon |
Clark |
| Before |
8 u |
5 u |
8 u |
| Change |
+ 2.4 u |
+ 4 u |
- 6.4 u |
| After |
10.4 u |
9 u |
1.6 u |
Number of coins that Clark gave to Brandon and Simon
=
45 x 8 u
= 6.4 u
Number of coins that Simon received from Clark
=
80100 x 5 u
= 4 u
Number of coins that Brandon received from Clark
= 6.4 u - 4 u
= 2.4 u
Number of less coins that Clark had less than Brandon
= 10.4 u - 1.6 u
= 8.8 u
8.8 u = 440
1 u = 440 ÷ 8.8 = 50
Number of coins that Brandon and Clark had
= 10.4 u + 1.6 u
= 12 u
= 12 x 50
= 600
Answer(s): 600
