Tommy, Brandon and Colin collected coins in the ratio of 11 : 7 : 5. After Colin gave
45 to Tommy and Brandon, Colin had 448 less coins than Tommy. The number of coins that Brandon had increased by 40%. How many coins did Tommy and Colin have in the end?
| |
Tommy |
Brandon |
Colin |
| Before |
11 u |
7 u |
5 u |
| Change |
+ 1.2 u |
+ 2.8 u |
- 4 u |
| After |
12.2 u |
9.8 u |
1 u |
Number of coins that Colin gave to Tommy and Brandon
=
45 x 5 u
= 4 u
Number of coins that Brandon received from Colin
=
40100 x 7 u
= 2.8 u
Number of coins that Tommy received from Colin
= 4 u - 2.8 u
= 1.2 u
Number of less coins that Colin had less than Tommy
= 12.2 u - 1 u
= 11.2 u
11.2 u = 448
1 u = 448 ÷ 11.2 = 40
Number of coins that Tommy and Colin had
= 12.2 u + 1 u
= 13.2 u
= 13.2 x 40
= 528
Answer(s): 528
