Perry, Lee and Christopher collected coins in the ratio of 9 : 4 : 5. After Christopher gave ⁷₁₀ to Perry and Lee, Christopher had 258 less coins than Perry. The number of coins that Lee had increased by 60%. How many coins did Perry and Christopher have in the end?

	Perry	Lee	Christopher
Before	9 u	4 u	5 u
Change	+ 1.1 u	+ 2.4 u	- 3.5 u
After	10.1 u	6.4 u	1.5 u

Number of coins that Christopher gave to Perry and Lee
= ⁷₁₀ x 5 u
= 3.5 u

Number of coins that Lee received from Christopher
= ⁶⁰₁₀₀ x 4 u
= 2.4 u

Number of coins that Perry received from Christopher
= 3.5 u - 2.4 u
= 1.1 u

Number of less coins that Christopher had less than Perry
= 10.1 u - 1.5 u 
= 8.6 u

8.6 u = 258

1 u = 258 ÷ 8.6 = 30

Number of coins that Perry and Christopher had
= 10.1 u + 1.5 u
= 11.6 u
= 11.6 x 30
= 348

Answer(s): 348