Michael, Zeph and Cole collected coins in the ratio of 12 : 9 : 5. After Cole gave
15 to Michael and Zeph, Cole had 162 less coins than Michael. The number of coins that Zeph had increased by 10%. How many coins did Michael and Cole have in the end?
| |
Michael |
Zeph |
Cole |
| Before |
12 u |
9 u |
5 u |
| Change |
+ 0.1 u |
+ 0.9 u |
- 1 u |
| After |
12.1 u |
9.9 u |
4 u |
Number of coins that Cole gave to Michael and Zeph
=
15 x 5 u
= 1 u
Number of coins that Zeph received from Cole
=
10100 x 9 u
= 0.9 u
Number of coins that Michael received from Cole
= 1 u - 0.9 u
= 0.1 u
Number of less coins that Cole had less than Michael
= 12.1 u - 4 u
= 8.1 u
8.1 u = 162
1 u = 162 ÷ 8.1 = 20
Number of coins that Michael and Cole had
= 12.1 u + 4 u
= 16.1 u
= 16.1 x 20
= 322
Answer(s): 322
