Lee, Wesley and Clark collected coins in the ratio of 9 : 10 : 6. After Clark gave
35 to Lee and Wesley, Clark had 134 less coins than Lee. The number of coins that Wesley had increased by 35%. How many coins did Lee and Clark have in the end?
| |
Lee |
Wesley |
Clark |
| Before |
9 u |
10 u |
6 u |
| Change |
+ 0.1 u |
+ 3.5 u |
- 3.6 u |
| After |
9.1 u |
13.5 u |
2.4 u |
Number of coins that Clark gave to Lee and Wesley
=
35 x 6 u
= 3.6 u
Number of coins that Wesley received from Clark
=
35100 x 10 u
= 3.5 u
Number of coins that Lee received from Clark
= 3.6 u - 3.5 u
= 0.1 u
Number of less coins that Clark had less than Lee
= 9.1 u - 2.4 u
= 6.7 u
6.7 u = 134
1 u = 134 ÷ 6.7 = 20
Number of coins that Lee and Clark had
= 9.1 u + 2.4 u
= 11.5 u
= 11.5 x 20
= 230
Answer(s): 230
