Pierre, David and Cooper collected pens in the ratio of 7 : 4 : 10. After Cooper gave
710 to Pierre and David, Cooper had 92 less pens than Pierre. The number of pens that David had increased by 45%. How many pens did Pierre and Cooper have in the end?
| |
Pierre |
David |
Cooper |
| Before |
7 u |
4 u |
10 u |
| Change |
+ 5.2 u |
+ 1.8 u |
- 7 u |
| After |
12.2 u |
5.8 u |
3 u |
Number of pens that Cooper gave to Pierre and David
=
710 x 10 u
= 7 u
Number of pens that David received from Cooper
=
45100 x 4 u
= 1.8 u
Number of pens that Pierre received from Cooper
= 7 u - 1.8 u
= 5.2 u
Number of less pens that Cooper had less than Pierre
= 12.2 u - 3 u
= 9.2 u
9.2 u = 92
1 u = 92 ÷ 9.2 = 10
Number of pens that Pierre and Cooper had
= 12.2 u + 3 u
= 15.2 u
= 15.2 x 10
= 152
Answer(s): 152
