David, Albert and Cole collected coins in the ratio of 10 : 5 : 9. After Cole gave
710 to David and Albert, Cole had 106 less coins than David. The number of coins that Albert had increased by 60%. How many coins did David and Cole have in the end?
| |
David |
Albert |
Cole |
| Before |
10 u |
5 u |
9 u |
| Change |
+ 3.3 u |
+ 3 u |
- 6.3 u |
| After |
13.3 u |
8 u |
2.7 u |
Number of coins that Cole gave to David and Albert
=
710 x 9 u
= 6.3 u
Number of coins that Albert received from Cole
=
60100 x 5 u
= 3 u
Number of coins that David received from Cole
= 6.3 u - 3 u
= 3.3 u
Number of less coins that Cole had less than David
= 13.3 u - 2.7 u
= 10.6 u
10.6 u = 106
1 u = 106 ÷ 10.6 = 10
Number of coins that David and Cole had
= 13.3 u + 2.7 u
= 16 u
= 16 x 10
= 160
Answer(s): 160
