Sean and Neave started on a 45-km cycling trip at the same time. They cycled at the same speed for first 10 km. For the remaining 35 km, Sean cycled faster than Neave. He arrived at the finishing point 30 minutes before Neave who was 10 km behind him. Neave did not change his speed throughout and completed it at 09 25.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Sean's average speed for the remaining 35 km of the trip in km/h?
(a)
60 min = 1 h
30 min =
3060 h =
12 Neave's average speed
= 10 ÷
12 = 20 km/h
Time that Neave took for the trip
= 45 ÷ 20
= 2
520 h
= 2
14 h
= 2 h 15 min
2 h 15 min before 09 25 is 07 10.
(b)
To find the time that Sean took for the remaining 35 km of the trip, we need to use the time that Neave took subtract that of the time taken for first 10 km and the time that Sean was faster than Neave.
Time that Sean took for the remaining 35 km of the trip
= 2
14 -
12 -
12 = 1
14 h
Sean's average speed
= 35 ÷ 1
14 = 28 km/h
Answer(s): (a) 07 10; (b) 28 km/h