Fabian and Zane started on a 48-km cycling trip at the same time. They cycled at the same speed for first 5 km. For the remaining 43 km, Fabian cycled faster than Zane. He arrived at the finishing point 20 minutes before Zane who was 5 km behind him. Zane did not change his speed throughout and completed it at 08 30.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Fabian's average speed for the remaining 43 km of the trip in km/h?
(a)
60 min = 1 h
20 min =
2060 h =
13 Zane's average speed
= 5 ÷
13 = 15 km/h
Time that Zane took for the trip
= 48 ÷ 15
= 3
315 h
= 3
15 h
= 3 h 12 min
3 h 12 min before 08 30 is 05 18.
(b)
To find the time that Fabian took for the remaining 43 km of the trip, we need to use the time that Zane took subtract that of the time taken for first 5 km and the time that Fabian was faster than Zane.
Time that Fabian took for the remaining 43 km of the trip
= 3
15 -
13 -
13 = 2
815 h
Fabian's average speed
= 43 ÷ 2
815 = 16
3738 km/h
Answer(s): (a) 05 18; (b) 16
3738 km/h