Asher and Pierre started on a 35-km cycling trip at the same time. They cycled at the same speed for first 5 km. For the remaining 30 km, Asher cycled faster than Pierre. He arrived at the finishing point 20 minutes before Pierre who was 5 km behind him. Pierre did not change his speed throughout and completed it at 09 30.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Asher's average speed for the remaining 30 km of the trip in km/h?
(a)
60 min = 1 h
20 min =
2060 h =
13 Pierre's average speed
= 5 ÷
13 = 15 km/h
Time that Pierre took for the trip
= 35 ÷ 15
= 2
515 h
= 2
13 h
= 2 h 20 min
2 h 20 min before 09 30 is 07 10.
(b)
To find the time that Asher took for the remaining 30 km of the trip, we need to use the time that Pierre took subtract that of the time taken for first 5 km and the time that Asher was faster than Pierre.
Time that Asher took for the remaining 30 km of the trip
= 2
13 -
13 -
13 = 1
23 h
Asher's average speed
= 30 ÷ 1
23 = 18 km/h
Answer(s): (a) 07 10; (b) 18 km/h