Peter and Fabian started on a 45-km cycling trip at the same time. They cycled at the same speed for first 10 km. For the remaining 35 km, Peter cycled faster than Fabian. He arrived at the finishing point 30 minutes before Fabian who was 10 km behind him. Fabian did not change his speed throughout and completed it at 07 25.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Peter's average speed for the remaining 35 km of the trip in km/h?
(a)
60 min = 1 h
30 min =
3060 h =
12 Fabian's average speed
= 10 ÷
12 = 20 km/h
Time that Fabian took for the trip
= 45 ÷ 20
= 2
520 h
= 2
14 h
= 2 h 15 min
2 h 15 min before 07 25 is 05 10.
(b)
To find the time that Peter took for the remaining 35 km of the trip, we need to use the time that Fabian took subtract that of the time taken for first 10 km and the time that Peter was faster than Fabian.
Time that Peter took for the remaining 35 km of the trip
= 2
14 -
12 -
12 = 1
14 h
Peter's average speed
= 35 ÷ 1
14 = 28 km/h
Answer(s): (a) 05 10; (b) 28 km/h