Ryan and Flynn started on a 55-km cycling trip at the same time. They cycled at the same speed for first 5 km. For the remaining 50 km, Ryan cycled faster than Flynn. He arrived at the finishing point 12 minutes before Flynn who was 5 km behind him. Flynn did not change his speed throughout and completed it at 07 30.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Ryan's average speed for the remaining 50 km of the trip in km/h?
(a)
60 min = 1 h
12 min =
1260 h =
15 Flynn's average speed
= 5 ÷
15 = 25 km/h
Time that Flynn took for the trip
= 55 ÷ 25
= 2
525 h
= 2
15 h
= 2 h 12 min
2 h 12 min before 07 30 is 05 18.
(b)
To find the time that Ryan took for the remaining 50 km of the trip, we need to use the time that Flynn took subtract that of the time taken for first 5 km and the time that Ryan was faster than Flynn.
Time that Ryan took for the remaining 50 km of the trip
= 2
15 -
15 -
15 = 1
45 h
Ryan's average speed
= 50 ÷ 1
45 = 27
79 km/h
Answer(s): (a) 05 18; (b) 27
79 km/h