Flynn and Cody started on a 45-km cycling trip at the same time. They cycled at the same speed for first 10 km. For the remaining 35 km, Flynn cycled faster than Cody. He arrived at the finishing point 30 minutes before Cody who was 10 km behind him. Cody did not change his speed throughout and completed it at 09 30.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Flynn's average speed for the remaining 35 km of the trip in km/h?
(a)
60 min = 1 h
30 min =
3060 h =
12 Cody's average speed
= 10 ÷
12 = 20 km/h
Time that Cody took for the trip
= 45 ÷ 20
= 2
520 h
= 2
14 h
= 2 h 15 min
2 h 15 min before 09 30 is 07 15.
(b)
To find the time that Flynn took for the remaining 35 km of the trip, we need to use the time that Cody took subtract that of the time taken for first 10 km and the time that Flynn was faster than Cody.
Time that Flynn took for the remaining 35 km of the trip
= 2
14 -
12 -
12 = 1
14 h
Flynn's average speed
= 35 ÷ 1
14 = 28 km/h
Answer(s): (a) 07 15; (b) 28 km/h