Asher and Ivan started on a 55-km cycling trip at the same time. They cycled at the same speed for first 10 km. For the remaining 45 km, Asher cycled faster than Ivan. He arrived at the finishing point 24 minutes before Ivan who was 10 km behind him. Ivan did not change his speed throughout and completed it at 07 25.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Asher's average speed for the remaining 45 km of the trip in km/h?
(a)
60 min = 1 h
24 min =
2460 h =
25 Ivan's average speed
= 10 ÷
25 = 25 km/h
Time that Ivan took for the trip
= 55 ÷ 25
= 2
525 h
= 2
15 h
= 2 h 12 min
2 h 12 min before 07 25 is 05 13.
(b)
To find the time that Asher took for the remaining 45 km of the trip, we need to use the time that Ivan took subtract that of the time taken for first 10 km and the time that Asher was faster than Ivan.
Time that Asher took for the remaining 45 km of the trip
= 2
15 -
25 -
25 = 1
25 h
Asher's average speed
= 45 ÷ 1
25 = 32
17 km/h
Answer(s): (a) 05 13; (b) 32
17 km/h