Fabian and Flynn started on a 50-km cycling trip at the same time. They cycled at the same speed for first 10 km. For the remaining 40 km, Fabian cycled faster than Flynn. He arrived at the finishing point 40 minutes before Flynn who was 10 km behind him. Flynn did not change his speed throughout and completed it at 08 30.
- At what time did the trip begin? Give the answer in 12-hour format.
- What was Fabian's average speed for the remaining 40 km of the trip in km/h?
(a)
60 min = 1 h
40 min =
4060 h =
23 Flynn's average speed
= 10 ÷
23 = 15 km/h
Time that Flynn took for the trip
= 50 ÷ 15
= 3
515 h
= 3
13 h
= 3 h 20 min
3 h 20 min before 08 30 is 05 10.
(b)
To find the time that Fabian took for the remaining 40 km of the trip, we need to use the time that Flynn took subtract that of the time taken for first 10 km and the time that Fabian was faster than Flynn.
Time that Fabian took for the remaining 40 km of the trip
= 3
13 -
23 -
23 = 2 h
Fabian's average speed
= 40 ÷ 2
= 20 km/h
Answer(s): (a) 05 10; (b) 20 km/h