In the figure, not drawn to scale. MNPQ is a square. PQR is an equilateral triangle and MP is a straight line. Find
- One-third of ∠MSR
- Five times of ∠RPS
(a)
∠QMP = 45° (Right angle)
∠SQP = 60° (Equilateral triangle)
∠MQS
= 90° - ∠SQP
= 90° - 60°
= 30°
∠MSR
= 30° + 45° (Exterior angle of a triangle)
= 75°
One-third of ∠MSR
=
13 x 75°
= 25°
(b)
∠RSP
= 180° - ∠MSR
= 180° - 75°
= 105° (Angles on a straight line)
∠RPS
= 180° - 60° - 105°
= 15° (Angles sum of triangle)
Five times of ∠RPS
= 5 x 15°
= 75°
Answer(s): (a) 25°; (b) 75°
